Mrv1909 12201918362D 17 16 0 0 0 0 999 V2000 1.7881 0.4161 0.0000 P 0 0 0 0 0 0 0 0 0 0 0 0 2.5081 0.0029 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 2.2013 1.1302 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 0.3600 -0.4101 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -2.5081 0.4161 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 1.3751 -0.3039 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -1.7881 1.6554 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -1.7881 -1.6554 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -2.5081 -0.4101 0.0000 O 0 0 0 0 0 0 0 0 0 0 0 0 -0.3599 0.8291 0.0000 N 0 0 0 0 0 0 0 0 0 0 0 0 -1.0740 0.4161 0.0000 C 0 0 1 0 0 0 0 0 0 0 0 0 -1.0740 -0.4101 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 1.0740 0.8291 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 0.3600 0.4161 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -1.7881 0.8291 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -1.7881 -0.8233 0.0000 C 0 0 0 0 0 0 0 0 0 0 0 0 -0.3599 1.3426 0.0000 H 0 0 0 0 0 0 0 0 0 0 0 0 1 2 1 0 0 0 0 1 3 1 0 0 0 0 1 6 2 0 0 0 0 1 13 1 0 0 0 0 4 14 2 0 0 0 0 5 15 1 0 0 0 0 7 15 2 0 0 0 0 8 16 1 0 0 0 0 9 16 2 0 0 0 0 11 10 1 1 0 0 0 10 14 1 0 0 0 0 10 17 1 0 0 0 0 11 12 1 0 0 0 0 11 15 1 0 0 0 0 12 16 1 0 0 0 0 13 14 1 0 0 0 0 M END > DB03459 > drugbank > [H]N([C@@H](CC(O)=O)C(O)=O)C(=O)CP(O)(O)=O > InChI=1S/C6H10NO8P/c8-4(2-16(13,14)15)7-3(6(11)12)1-5(9)10/h3H,1-2H2,(H,7,8)(H,9,10)(H,11,12)(H2,13,14,15)/t3-/m0/s1 > ZZKNRXZVGOYGJT-VKHMYHEASA-N > C6H10NO8P > 255.1193 > 255.014402813 > 8 > 26 > -3.098809627825807 > 19.815665923158985 > 1 > 5 > 0 > 0 > (2S)-2-(2-phosphonoacetamido)butanedioic acid > -2.11 > -2.741082786666666 > -1.58 > 0 > -3 > 0 > -3 > 3.4648963044985917 > 1.6507486718808886 > 161.23 > 46.96680000000001 > 6 > 1 > 6.73e+00 g/l > N-{3-[4-(3-aminopropyl)piperazin-1-yl]propyl}-3-[2-(thiophen-2-yl)acetamido]-5-{[(2R,3R,4S,5R,6R)-3,4,5-trihydroxy-6-(hydroxymethyl)oxan-2-yl]oxy}benzamide > 0 > DB03459 > EXPT02494 > experimental > Sparfosic acid > ácido esparfósico; Acidum sparfosicum; N-(phosphonacetyl)-L-aspartic acid; N-(phosphonoacetyl)-L-aspartic acid; N-phosphonacetyl-L-aspartic acid; PALA; phosphonoacetyl-L-aspartic acid; Sparfosic acid $$$$